WebProve the following: tan6° tan42° tan66° tan78°= 1 - Mathematics and Statistics Advertisement Remove all ads Advertisement Remove all ads Sum Prove the following: … Webtana+tan (60+a)-tan (60-a)=3tan3a Let's use the sum-of-angles formula for tangent, tan (x+y) = (tanx + tany)/ (1 - tanx tany), along with tan60º = √3 tan (60º ± A) = (√3 ± tanA) / (1 ∓ (√3) tanA) = (1 ± (√3) tanA) (√3 ± tanA) / (1 - 3 tan²A) = (3 ± 4 tanA + (√3) tan²A) / (1 - 3 tan²A) tanA + tan (60º + A) - tan (60º - A)
prove tan6tan42tan66tan78=1 - Brainly.in
WebA=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan(60-x)tanxtan(60+x)=tan3x for x=18° we get tan42°tan18°tan78°=tan54° for x=6° we get … WebMay 18, 2024 · About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators ... crodamol gtcc hlb
Prove that tan 6°. tan 42°. tan 66°. tan 78° = 1. - Sarthaks
WebIf A=tan 6 tan 42 and B=cot 66 cot 78, then A/B=? A=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan (60-x)tanxtan (60+x)=tan3x for x=18° we get … WebIf A=tan 6 tan 42 and B=cot 66 cot 78, then A/B=? A=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan (60-x)tanxtan (60+x)=tan3x for x=18° we get tan42°tan18°tan78°=tan54°... (1) for x=6° we get tan54°tan6°tan66°=tan18°... (2) Eliminating tan54°between (1) and (2) we get tan6°tan42°tan66°tan78°=1 Hence A/B=1. Anthony … WebIf A=tan6 0tan42 0 and B=cot66 0cot78 0, then A A=2B B A=1/3 B C A= B D 3A=2B Hard Solution Verified by Toppr Correct option is A) Given A=tan6tan42 and B=cot66cot78 … crodasinic ls 30 inci name